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Find the zero of the polynomial function x^3+8x^2-11x-18
4 months ago
Q:
Find the zero of the polynomial function x^3+8x^2-11x-18
Accepted Solution
A:
Answer:The answer to your question is: (x - 2)(x + 9)(x + 1) Step-by-step explanation: x³ + 8x² - 11x - 18find the prime factors of 1818 2 9 3 Try : ± 1, ±2, ±3, ± 6,± 9 3 3 1 Synthetic division 1 8 -11 -18 2 2 20 18 1 10 9 0 First factor ( x - 2) x² + 10x + 9 = 0 (x + 9)(x + 1) = 0 polynomial of the form x² + bx + c x³ + 8x² - 11x - 18 = (x - 2)(x + 9)(x + 1)